"On The Electronic Composition of Matter and Energy" with Carl D. Anderson quotes, by Brian S. McMillan

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In the following version most of the associated
magnitudes and units for the actual Fundamental
Constants of Physics have been purposely left out for
reasons of brevity. Therefore, only the ratios or
proportions have been retained. And are reflected in
the associated description for each constant. For
example: The Constant of Molar Volume is reflected by
the application of the two units in the theory... such
as "number" times "meters" equal Volume. In other
words the mathematical placement of the constants
agree with the individual values which are yielded in
description as well as calculation... individually as
well as in concert. Every object in the theory has
it's counterpart in reality.
The associated constant immediately below left of the
yielded value is, in most cases, borrowed from the CRC
Handbook of Chemistry and Physics 79th Edition,
subtitled Fundamental Physical Constants.

>>1.511091462/10^32 kg = emu-electronic mass unit

>>18381 * 1.511091462/10^32 * 6.02213713 * 10^0
>>= 1.672671/10^27 kg mass proton
 
>>18406 * 1.511091462/10^32 * 6.02213713 * 10^0
>>= 1.674946/10^27 kg mass neutron

>>(18381+92380) * 1.511091462/10^32
>>= 1.6737/10^27 kg mass hydrogen

>>(18381+92380) * 1.511091462/10^32 * 6.02213713 *
10^23
>>= .0010079251 molar mass hydrogen
.00100794

>>(2.99792458^2 * 92380 * 2)^-1
>>= 6.02213713 Avogadro constant
6.0221367(36)

>>(1838.1/92380)^(1/2)
>>= 1.410573071 shielded proton moment
1.41057138(47)

>>10^5 Pa * 92380 * 2.4263/10^12 meter
>>= .0224141594 constant of molar volume
.02241410(19)

>>2.99792458^2 * 92380 * 2
>>= 1.660540068 amu-atomic mass unit
1.6605402(10)

>>((1.511091462 * 6.02213713)(92380-18381))^(1/2)/pi^2
>>= 8.314456705 molar gas constant 1st variation

>>((1.511091462 * 6.02213713)(92380-18380))^(1/2)/pi^2
>>= 8.314512886 molar gas constant
8.314510(70)

>>((1.511091462 / 6.02213713)(92380-18380))^(1/2)/pi^2
>>= 1.380658179 Boltzman constant
1.380658(12)

>>1.674946/2.99792458^2/92380/2.4263
>>= 8.314515515 molar gas constant

>>((18381+92380)/16.02187159)^(1/2)
>>= 8.314512885 molar gas constant
8.314510(70)

>>(92380+18381)/(92380-18380)/1.511091462*pi^4
>>= 9.648590782 Faraday constant
9.6485309(29)

>>(1-2.99792458^2/16.02187159)^(1/2)
>>= 6.626045764 Planck constant-Lorentz transformation

>>6.626045764/2.99792458/9.109388428
>>= 2.4263 de Broglie wave equation electron
2.42631058(22)

>>(1838.2/92380)^(1/2)
>>= 1.410611441 proton magnetic moment
1.41060761(47)

>>(1838.2 * 2.4263)^(1/3) * 2/3
>>= 1.097373565 Rydberg constant
1.0973731534(13)

>>10^5 Pa * 18382 * 2.4263/10^12 meter
>>= .0046002466 constant of nuclear volume
new constant (second generation)

>>(911 + pi)^(1/3) /4
>>= 2.4263 electron Compton wavelength-full abstract

>>6.02213713 * 2 * 92380 /4pi
>>= 8.854187818 permittivity constant
8.854187818

>>4pi/92380
>>= 13.60291255 eV binding energy hydrogen
13.6056981(40)

>>80*(92380/18380)^(1/3)
>>= 137.0358308 inverse fine-structure
137.0359895(61)

With the mathematically derived Rydberg constant
above which include the components of the electron
wavelength multiplied by the number of
electron/positron units which yield the value for the
proton magnetic moment... a new constant can now be
confirmed and added to the International Standard of
Units for the fundamental constants of physics. The
"constant of nuclear volume" (second generation)

This strongly indicates that the string of 92380
electron/positron units which forms a single orbital
around the nucleus of the hydrogen atom is connected
at all times with at least one or more of the 18381
electron/positron units which form the single proton
of that nucleus leading to a measurement of 18382
body of units and confirmed by the yield for the
constant of Rydberg as the result of a rotating or
precessing elliptical structure.

The actual relationship between the Rydberg constant
and the constant of molar volume then becomes
manifest as a proportion between the two values
for the Rydberg and electron wavelength constants
in connection with the hydrogen shell count of 92380
electrons, and yielding the proton magnetic moment,
borrowed from the CRC Handbook 79th edition as
given to 8,6 and 8 significant figures respectively.

>>((.10973731*3/2)^3/2.42631/92380)^(1/2)
>>= 1.410607637
1.41060761(47)

Of which Rydberg constant becomes a simplified
relationship between the proton magnetic moment
and the constant of molar volume... thus:

>> 2/3 * (1.410611441^2 * 2.24141594)^(1/3)
>>= 1.097373565 Rydberg constant
1.0973731534(13)

All current theories concerning the structure of the
hydrogen atom state that one electron surrounds a
single proton composed of three quarks... This is NOT
TRUE!
The hydrogen atom actually has a STRING of 92380
electron-positron units forming a "basket" or "web"
which encloses a single proton which is composed of
18381 electron-positron units alternating like black
and white pearls on a pearl necklace.
EVERYTHINGS ELECTRONS and heres PROOF!

>>1.511091462/10^32 kg * 6.02213713 * 10^23 *

>>(2*18381 + 2*18406 + 366273)
>>= .0040026077 molar mass helium
.00400260

>>(3*18381 + 4*18406 + 633981)
>>= .0069410068 molar mass lithium
.006941

>>(4*18381 + 5*18406 + 824796)
>>= .009012185 molar mass beryllium
.00901218

>>(5*18381 + 6*18406 + 985572)
>>= .0108100083 molar mass boron
.01081

>>(6*18381 + 6*18406 + 1099185)
>>= .012111537 molar mass carbon
.0121115

>>(7*18381 + 7*18406 + 1281689)
>>= .0140067018 molar mass nitrogen
.0140067

>>(8*18381 + 8*18406 + 1463880)
>>= .0159994016 molar mass oxygen
.0159994

>>(9*18381 + 10*18406 + 1738248)
>>= .0189984067 molar mass fluorine
.01899840

>>(10*18381 + 10*18406 + 1849603)
>>= .0201790043 molar mass neon
.020179

>>(11*18381 + 12*18406 + 2103286)
>>= .0229897759 molar mass sodium
.02298977

Since all atoms larger than hydrogen, are
theoretically based to be built upon the structural
constraints for the ground state of hydrogen. This
means that the nuclei as well as the shells of all
atoms are a real and continuous construction, made up
of finite parts or individual units of electron, which
ultimately dictates the dimensional boundaries of the
molecule.

          Signed: Brian S. McMillan "LUCKY MAN"

PS: The values for the elements above are based upon,
Appendix E, A26. Periodic Table of the Elements.
Physics Parts 1 and 2. Halliday-Resnick. Third
Edition.

PSS: The following expansion for the shielded proton
magnetic moment has been included only as an example
for scientific scrutiny. As the simplified
representation is a more accurate reflection for the
interaction of the integral parts and should be seen
through the eyes of a more well rounded theory.

>>(1/2*10^-5 Pa*18381/92380^2/6.02213713/10^23/
>>2.99792458^2/10^16)^(1/2) = 1.410573071/10^26 J T^-1
>>U'p exact

PPSS: Every electron is composed of two
neutrino...however that is another matter... heh heh!
NEXT: On The Nature of Gravity

Between the two values... that of hydrogen and the
proton, only one of these can be empirically
measured... Can you guess which one....You got it!
Hydrogen. Because, the hydrogen atom can be
measured directly by concentrating an enormous
number of atoms in a container. And since the
weight of the container is known and through
Avogadro's law, the approximate number of atoms in
the container may be obtained. We separate the
weight of the container from the weight of the
hydrogen gas and voila!

HENCE: 92380 * 2^(1/2) * 2.81794092/10^15 /2pi/
5.29177249 * 10^11 = 1.107245201 times nuclear
circumference.

Which means that with the dimensional radius of the
electron and hydrogen atom thought to be known, we
can now take our electron-positron shell count and
multiply it by the square root of two times the
radius of the electron, which is a direct way of
measuring permeability as an exact geometric
parameter, and then dividing by the Bohr
circumference to yield the number of times the
electron string makes a complete revolution around
the nucleus...

If the above yield for the number of times the
electron-positron string circles the nucleus is
correct.
That is only about 1.1 times... then this means
that the shell of the hydrogen atom is probably
elliptical, and operates in connection with the
proton to yield all of the values of spectra as
well as the ionization constants
and binding energies.

One last equation in support of the this model.

IF: 5.291804717/10^11 = Bohr radius (close approx.)

THEN: (5.291804717/10^11)^3/9.80665
>>= 1.511091462/10^32 kg emu-electronic mass unit

Question from U.E

> >>1.511091462/10^32 kg = emu-electronic mass unit

What is this unit? It is electronmass / (N_A *
10^-22)?
N_A is Avogadros number (6.02213713*10^23). Then you
are using
an electron mass with only two or three significant
digits!

Regards, censored

Response to U.E.

How do you know, that it is not the other way around?
In other words the free electron mass can be derived
thus:

IF: 1.511091462/10^32 kg/
>>(1-2.99751208^2/2.99792458^2)^(1/2)
>>= 9.109385168/10^31 kg

OR: 9.1/10^32/(1-2.982928332^2/2.99792458^2)^(1/2)
>>= 9.109388561/10^31 kg

This application of the Lorentz Transformation,
illustrates how easy it might be to demonstrate a
relationship between the actual mass or bound mass
of the electron and an accelerated mass or free
electron mass that is currently recognized in
International Standard Units.

There are other candidates for the electron mass
unit, as well as for the proton and total hydrogen
count... however, all are derivatives of
10^23 * 9.1/10^32 * (18381 + 92380)
>>= .0010079251 molar mass hydrogen

IF: 9.1/10^32 kg * 18381 = 1.672671/10^27 kg

Since, in the first case we obtain the molar mass of
the hydrogen atom and in the second case we achieve
the kilogram mass-both from 9.1/10^32... and, of the
two recognized values... since hydrogen is the only
one that can be empirically determined we must base
the kilogram value on the unit which yields the mass
of hydrogen in kilograms.
However, there are values which are derivatives that
will also work equally well... It is merely a
coincidence that the electronic mass unit is so
close to 9.1... the actual value may be closer to
9.09994.../10^9/6.02213713/10^23
>>= 1.511081499/10^32 kg or something else!

Einstein, proposed that as objects approach the speed
of light, that they will appear to increase in mass.
>From this, I was able to determine that the free
electron mass in SI was in fact an accelerated mass...
That is NOT a true REST MASS.
                                
                             Thank You A.E.
                             Signed Brian S. McMillan

PS. The original base values yield a set of
relationships with those values and the fundamental
constants as well as the table of the elements that
cannot easily be dismissed.

IF: 10^-5 * 9.1/10^32 * 2.99792458*10^8 *
>>(2.99792458 + pi) = 1.674928676/10^27 kg

ALSO: ((1838.1/92380)^(1/2) * 2 * 3^6 * 91^-1
>>/(92380-18381)/(18381+92380))^(1/2)
>>= 1.660540608 atomic mass unit (abstract)
To seven significant figures.

THEN: 2 * 3^6 /91 = 16.02197802 electronic charge
(abstract)

IF: 1.235595178*10^20 * 6.626045764/10^34
>>= 8.187110915/10^14 mc^2

AND: r^(3/2) = Period of revolution, Johannes Kepler

AND: 3/2pi * 10^20 * (5.291791777/10^11)^(3/2)
>>= 18380 proton-emu count -1

THEN: 3/20pi/10^5Pa * 1.235595178*10^20
>> * (5.291791777/10^11)^(3/2) = .02271023937
Loschmidt
constant (approximate)

Substitution of the Bohr radius in Johannes Kepler's
periodic equation in concert with the
electromagnetic frequency constant and then dividing
by two thirds pi to yield the Loschmidt constant of
molar volume is consistent with
the previous equation for the electronic mass unit
derived above with use of the gravitational
acceleration constant.

IF: 1/2 * ((92380+2)/137.036)^3 /2.99792458/10^8
>>= .5109840708 /10^6 MeV electron emissions energy
(abstract)

THEN: 10^-5 Pa * 6 * ((92380-1)/137.036)^3
>> approx.= 18381 proton-emu count

IF: (18380/92380)^(1/3)*3/4pi/(2.4263*1838.2)^(1/3)/16
>>= 5.291776636 Bohr radius hydrogen
5.29177249(24)

AND: (5.291776636/10^11)^3/9.80665
>>= 1.511067406/10^32 kg emu-theoretic value

AND: 1.511067406/10^32 kg * 18381 * 6.02213713*10^0
>>= 1.672644372/10^27 kg accelerated mass proton SI

AND: 1.511067406/10^32 kg * 18406 * 6.02213713*10^0
>>= 1.674919336/10^27 kg accelerated mass neutron SI

THEN:1.511067406/10^32 kg * (18382+92381)
>>= 1.673703591/10^27 kg mass hydrogen (h+)

ALSO:1.673703591/10^27 kg * 6.02213713*10^23
>>= .001007927254 molar mass hydrogen (h+)

"Lucky Man" Santa Rosa, California

The following excerpt, copied from the original text,
by
Carl D. Anderson on the "Production and Properties of
Positrons";
Nobel lecture presented at Stockholm, December 12,
1936, pp.
9-10, subtitled "Positrons of High Energy". Supports
first
principals with regard to the electronic composition
of cosmic
radiation. That is the nucleus of hydrogen and helium
atoms,
as well as the optical component of gamma radiation as
observed by Anderson between 1931-1932.

"At present, however, it is very difficult to doubt
that the highly
absorbable component of the primary cosmic-ray beam
consists
largely of electrons absorbed principally through the
mechanisms
discussed above, which give rise to the electron
showers."

"Until quite recently it was not clear that the high
energy positive
and negative electrons which have now been shown to
exhibit a
high absorbability behaved in a manner essentially
differently
from the cosmic-ray particles of highly penetrating
character.
These highly penetrating particles, although not free
positive and
negative electrons, appear to consist of both positive
and
negative particles of unit electric charge, and will
provide
interesting material for future study."

Review of the evidence:

At first, I had reviewed this material with some
caution, because
in Andersons day, the definition of all the objects
detected in his
experiments, had not yet been fully agreed upon; that
is
Anderson refers to all subatomic particles directly
detected as
"electrons" or indirectly as "photons" possibly
gamma-rays. However, since Anderson had not yet
discovered the existence of the meson 'which he did do
later on' and any of the positively charged
by-products produced by cosmic-rays ploughing through
a lead barrier within the Wilson Cloud Chamber
apparatus were
compared to the energies associated with what we now
recognize
to be the classic "electron" of the lepton class.

Anderson makes a clear distinction between "free
positive and negative electrons" and those "high
energy electrons" of a more direct cosmic origin, to
which the free positive and negative electrons
produced in the cloud chamber were not produced from
material being knocked out of the barrier itself...
but were clearly defined as being from a compounded
cosmic-ray source.

So it would appear that Carl D. Anderson was the first
person to
directly observe the electronic decomposition of the
gamma-ray
photon as well as the electronic decomposition of the
nuclei of
atoms.

                
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